2(x^2+2x-440)=0

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Solution for 2(x^2+2x-440)=0 equation:


Simplifying
2(x2 + 2x + -440) = 0

Reorder the terms:
2(-440 + 2x + x2) = 0
(-440 * 2 + 2x * 2 + x2 * 2) = 0
(-880 + 4x + 2x2) = 0

Solving
-880 + 4x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-440 + 2x + x2) = 0

Factor a trinomial.
2((-22 + -1x)(20 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-22 + -1x)' equal to zero and attempt to solve: Simplifying -22 + -1x = 0 Solving -22 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '22' to each side of the equation. -22 + 22 + -1x = 0 + 22 Combine like terms: -22 + 22 = 0 0 + -1x = 0 + 22 -1x = 0 + 22 Combine like terms: 0 + 22 = 22 -1x = 22 Divide each side by '-1'. x = -22 Simplifying x = -22

Subproblem 2

Set the factor '(20 + -1x)' equal to zero and attempt to solve: Simplifying 20 + -1x = 0 Solving 20 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-20' to each side of the equation. 20 + -20 + -1x = 0 + -20 Combine like terms: 20 + -20 = 0 0 + -1x = 0 + -20 -1x = 0 + -20 Combine like terms: 0 + -20 = -20 -1x = -20 Divide each side by '-1'. x = 20 Simplifying x = 20

Solution

x = {-22, 20}

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